append()和extend()和insert()
a = [1,2,3,4,5]
a.append([6,7,8])
print(a)
b = [1,2,3,4,5]
b.extend([6,7,8])
print(b)
c = [1,2,3,4,5]
c.insert(3,10)
print(c)[1, 2, 3, 4, 5, [6, 7, 8]][1, 2, 3, 4, 5, 6, 7, 8][1, 2, 3, 10, 4, 5]假定给出一个列表 member = “图灵”, “的”, “周老师”, “是最帅的”
想要把member变成 member = “图灵”, 99, “的”,88, “周老师”,77, “是最帅的”, 666应该怎么做？
member = ["图灵", "的", "周老师", "是最帅的"]
member.insert(1,99)
member.insert(3,88)
member.insert(5,77)
member.append(666)
print(member)['图灵', 99, '的', 88, '周老师', 77, '是最帅的', 666]请问如何将下边这个列表的”图灵学院”修改为”周老师”？
ls = [1, [1, 2, ['图灵学院']], 3, 5, 8, 13, 18]ls = [1, [1, 2, ['图灵学院']], 3, 5, 8, 13, 18]
ls[1][2][0] = "周老师"
print(ls)[1, [1, 2, ['周老师']], 3, 5, 8, 13, 18]将列表推导式还原出来
ls = [(x, y) for x in range(10) for y in range(10) if x%2 == 0 if y %2 == 0]ls = [(x, y) for x in range(10) for y in range(10) if x%2 == 0 if y %2 == 0]
print(ls)[(0, 0), (0, 2), (0, 4), (0, 6), (0, 8), (2, 0), (2, 2), (2, 4), (2, 6), (2, 8), (4, 0), (4, 2), (4, 4), (4, 6), (4, 8), (6, 0), (6, 2), (6, 4), (6, 6), (6, 8), (8, 0), (8, 2), (8, 4), (8, 6), (8, 8)]ls = []
for x in range(10):
for y in range(10):
if x%2 == 0 and y %2 == 0:
ls.append((x,y))
print(ls) [(0, 0), (0, 2), (0, 4), (0, 6), (0, 8), (2, 0), (2, 2), (2, 4), (2, 6), (2, 8), (4, 0), (4, 2), (4, 4), (4, 6), (4, 8), (6, 0), (6, 2), (6, 4), (6, 6), (6, 8), (8, 0), (8, 2), (8, 4), (8, 6), (8, 8)]正文完