1. 编写一个函数（不要使用python模块的函数），打乱列表元素的顺序
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
import random
# 方案1
def random_list1(a):
for i in range(0, 100):
index1 = random.randint(0, len(a)-1)
index2 = random.randint(0, len(a)-1)
a[index1], a[index2] = a[index2], a[index1]
return a
b = random_list1(a)
print(b)[4, 3, 7, 1, 9, 2, 5, 8, 0, 6]# 方案2
def random_list2(a):
a_copy = a.copy()
result = []
count = len(a)
for i in range(0, count):
index = random.randint(0, len(a_copy)-1)
result.append(a_copy[index])
del a_copy[index]
return result
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
b = random_list2(a)
print(b)[4, 0, 5, 1, 2, 7, 9, 3, 8, 6]2. 如何对列表元素进行随机排列
a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
random.shuffle(a)
print(a)[2, 3, 1, 4, 8, 0, 9, 7, 5, 6]正文完